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Akrona
10-31-2015, 01:17 AM
I've been re-reading my favorite manga, 666 Satan, when I noticed a little detail that I never noticed before. One of the minor protagonists, named Kaito, uses an O Part suit of armor that increases and decreases in weight on command, and uses it to pin an enemy to the ground.

Just how heavy can it get, you ask? This heavy.

http://i1.ilist.me/s/666Satan/0066-014.png
http://i1.ilist.me/s/666Satan/0066-015.png
http://i1.ilist.me/s/666Satan/0066-016.png
http://i1.ilist.me/s/666Satan/0066-017.png
http://i1.ilist.me/s/666Satan/0066-018.png

Does anyone know a way to calculate the weight of the armor, and the force it took to crack the ice like that? I'll admit, I mostly just wanna know out of bored curiosity :distracted

R
10-31-2015, 08:36 AM
is this regular ice? some reinforced ice? some magical ice from his opponent?

regular ice has a density of 0.917g/cm^3

going from this pics he cracked the surface in a given radius and then fell down in the hollow cave. is this correct?

Skydragon
10-31-2015, 08:37 AM
good guy raven

Akrona
10-31-2015, 03:01 PM
is this regular ice? some reinforced ice? some magical ice from his opponent?

regular ice has a density of 0.917g/cm^3

going from this pics he cracked the surface in a given radius and then fell down in the hollow cave. is this correct?
The ice is just normal ice as far as I know. I'm not sure if it was a hollow cave below them, but it kind of implies the pit was made by the impact of Kaito's weight. He said that if he kept increasing the weight he'd end up in the ocean.

R
10-31-2015, 05:15 PM
The ice is just normal ice as far as I know. I'm not sure if it was a hollow cave below them, but it kind of implies the pit was made by the impact of Kaito's weight. He said that if he kept increasing the weight he'd end up in the ocean.


alright i took a closer look. it does indeed look like after the initial breaking through the ice, he fell into water, which you can see at page 17 on the right side of the first panel (the little watermotions) and at page 18 on the first page on the left (the trail of oxygen as he lands on the bottom)

i as well found another picture which soldifies my assumption:

http://a.mangatown.com/store/manga/13/065.0/compressed/43.jpg?v=511921221787

the chapter before, where they arrive on the zone they show the water surrounding the ice.

meaning: the feat itself is not as great as one might think, since its only the superficial layer of ice which got destroyed (i will use pulverization to give him the benefit of the doubt. could as well be violently fragmented)

since the area of destruction its shaped like a prisma, to find its volume we first need its height.

i found this picture which showcases the ice at the edge of the hole is around triple as high as the persons before, before the water begins.

http://a.mangatown.com/store/manga/13/066.0/compressed/20.jpg?v=51192122179

average person: 1.70m

x 3

=5.1

the layer of ice is 5.1 meter thick

next we find the footprint. going by the pictures the footprint is around 4 1/2 times greater than the person in front (on the page you provided the whole was not complete broken. i went with the one i found.

average person: 1.70m

x 4.5

= 7.65

the footprint is 7.65m

----

solving for the volume we get 39m^3

x 916 for the density of ice

x 1 000 000

x 35724000000 cm^3

x 214.35 joules pulverization

= 7657439400000 joules

converting into tnt

1.83 kilotons

high end multi-city-block level

Akrona
11-10-2015, 10:27 PM
Anyone wanna help me figure out the size of a floating city? :imslow

Akrona
09-27-2016, 02:46 AM
The scaling :catgrin :
http://2.bp.blogspot.com/-Tfriy3ohges/VjM9muBAL7I/AAAAAAAAEN8/pYkfm3LlWHc/s16000/0062-033.jpg
http://2.bp.blogspot.com/-C6Mxkspw2qc/VjNCPPekWcI/AAAAAAAAFhg/c1Upp1dhMH4/s16000/0062-034.jpg
http://2.bp.blogspot.com/-WAhjOQ0Pcuk/VjNA2k7Uz8I/AAAAAAAAFII/rNOZRwrOpNs/s16000/0062-035.jpg


Shuri casually makes a giant hill of ice, that I only recently realized reaches above the clouds. Too bad Kite makes it look a lot smaller then I thought when he smashes it. :psyduck

Anyways, I thought it might be more impressive then it looks. He does seem to completely pulverize most of the ice, and he was only using 30% power. Anyone curious or bored enough to help me out and calc the creation/destruction of the ice?

McCree
09-27-2016, 03:11 AM
Way to many problems with this for me to calc it.

Those clouds must be like 45 feet of the ground.

But anyway...

If the scaling wasn't so fucked, id do it

Just take average cloud height, determine the height of the hill.

Then use the crater scan to determine the radius of the hill.

Volume of cylinder formula

Density of ice already mentioned above.

Energy value for violent fragmentation.

Voula.